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Savatey [412]
2 years ago
15

What is the solution set for this inequality?

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
8 0

Answer:

X<-4

Step-by-step explanation:

-3x+10>22

subtract 10 to both sides

-3x>12

divide by -3 on both sides

when you divide by a negative number you flip the sign so the answer will be x<-4

You might be interested in
James has read 1/8 of a book eric has read 1/3 of the same book what fraction more of the book has eric read than james
BARSIC [14]

1/3 = 8/24

1/8 = 3/24

use 24 since it's the LCM of 8 and 3

8-3/24 = 5/24

3 0
3 years ago
Also can anyone help with these problems too?
d1i1m1o1n [39]

Answer:

6. a

------

7. b

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8. d

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9. d

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7 0
3 years ago
A city known for its temperature extremes started the day at -5 degrees Fahrenheit. The temperature increased by 78 degrees Fahr
charle [14.2K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Starting temperature = - 5°F

Temperature at midday =increase in temperature by 78°F = (starting temperature + 78°F)

Temperature at nightfall = decrease in temperature by 32°F = ( temperature at midday - 32°F)

Temperature at midday:

(-5°F + 78°F) = 73°F

Temperature at nightfall:

(Temperature at midday - 32°F)

(73°F - 32°F) = 41°F

7 0
3 years ago
Coffee cost 18.96 for 3 pounds what is the cost per pound of c offee
Anna007 [38]

Answer:

$18.96 ÷ 3 pounds = 6.32 per coffee

5 0
2 years ago
Read 2 more answers
The areas of two similar octagons are 9 m² and 25 m². What is the scale factor of their side lengths? PLZ HELP PLZ PLZ PLZ
torisob [31]

Answer:

\frac{3}{5}

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

\frac{9}{25} = (\frac{x}{y})^2 (area of similar polygons theorem)

The scale factor of their sides would be \frac{x}{y}. Which is:

\sqrt{\frac{9}{25}} = \frac{x}{y}

\frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y}

\frac{3}{5} = \frac{x}{y}

Scale factor of their sides = \frac{3}{5}

6 0
2 years ago
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