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3 years ago

State the Pythagorean theorem using the triangle shown below

Mathematics

2 answers:

AlekseyPX3 years ago

7 0

Answer: p^2 + q^2 = r^2

Step-by-step explanation:

Pythagorean Theorem = a^2 + b^2 = c^2

P = a (leg)

q = b (leg)

r = c (Hypotenuse)

Gemiola [76]3 years ago

3 0

Answer:

p^2+q^2=r^2 (the third option)

Step-by-step explanation:

The Pythagorean theorem states that each side not the hypotenuse squared equals the hypotenuse squared.

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um pai tem hoje 54 anos e seus quatro filhos tem juntos 39 anos. dentro de quantos anos a idade do pai será a soma da idade dos

Elan Coil [88]

a1 + r.N = b1 + R.N

54 + 1.N = 39 + 4.N

4.N - 1.N = 54 - 39

3.N = 15

N = 15 / 3

N = 5 anos

8 0

3 years ago

Sketch a graph of the relation y+4=2(x-3)

Aleks04 [339]

Answer:

I graphed it for you. Is this what you were looking for?

6 0

3 years ago

(5x - 4)²<br>plsss givee the solutionnn.

Natalija [7]

Answer:

= 25x² - 40x + 16

Step-by-step explanation:

(5x - 4)²

= (5x - 4) (5x - 4)

= 25x² - 20x - 20x + 16

= 25x² - 40x + 16

Hope this helps :)

Let me know if there are any mistakes!!

5 0

3 years ago

What expression is equivalent to 4^7 times 4^-5

liubo4ka [24]

All you have to do is add exponents when multiplying like monomials. So it's just 4^2

6 0

4 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

4 0

3 years ago