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Andrej [43]
3 years ago
15

−0.7+

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

-0.7+\frac{2}{8} =

[minus, 0, point, 7, plus, 2, divided by, 8, equals]

You can make the denominators the same to combine them, so you can multiply -0.7 by \frac{8}{8}

-0.7(\frac{8}{8})+\frac{2}{8}

-\frac{5.6}{8}+\frac{2}{8}=-\frac{3.6}{8}= - 0.45

Phoenix [80]3 years ago
4 0

ANSWER

- 0.7 +  \frac{2}{8}  = -0.45

EXPLANATION

We want to simplify;

- 0.7 +  \frac{2}{8}

Simplify the fraction:

- 0.7 +  \frac{1}{4}

This is now the same as:

0.25 - 0.7

We perform the subtraction to obtain,

-0.45

Therefore

- 0.7 +  \frac{2}{8}  = -0.45

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Find the first five terms of the sequence in which a1 = –10 and an = 4an – 1 + 7, if n ≥ 2.
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The first five terms of the sequence are -10, -33, -125, -493, -1965

Explanation:

The given expression is a_n=4a_{n-1}+7

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We need to determine the first five terms of the sequence.

<u>Second term:</u>

Substituting n = 2 in the expression a_n=4a_{n-1}+7, we have,

a_2=4a_{2-1}+7

a_2=4a_1+7

a_2=4(-10)+7

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<u>Third term:</u>

Substituting n = 3 in the expression a_n=4a_{n-1}+7, we have,

a_3=4a_2+7

a_3=4(-33)+7

a_3=132+7=-125

Thus, the third term is -125

<u>Fourth term</u><u>:</u>

Substituting n = 4 in the expression a_n=4a_{n-1}+7, we have,

a_4=4a_3+7

a_4=4(-125)+7

a_4=-500+7=-493

Thus, the fourth term is -493

<u>Fifth term</u>:

Substituting n = 5 in the expression a_n=4a_{n-1}+7, we have,

a_5=4a_4+7

a_5=4(-493)+7

a_5=-1972+7=-1965

Thus, the fifth term is -1965

Hence, the first five terms of the sequence are -10, -33, -125, -493, -1965

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