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arlik [135]
3 years ago
12

2(6x+3) hurry please thanks

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

Answer:

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░░░░▄▄▄██▀▀▀▀░░░░░░░

░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

▄░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take

░░░░░░░▀███▀█░▄░░ Over brainly

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░░░░░░█░░░░░░░░█░

Step-by-step explanation:

btw the answer is

(12x+6)

You might be interested in
Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)
TEA [102]

Answer:

<h2>a. \:  {x}^{2}  + 2</h2>

<h2> </h2><h2>b. \: 2 {x}^{2}  - 5x</h2><h2> </h2><h2>c. \: 6 {x}^{2}  + 8x</h2><h3> </h3><h3>d. \: 6 {x}^{2}  - 12x</h3>

solution,

a. \: x(x + 2) \\  \:  \:  = x \times x + 2 \times x \\  \:  \:  =  {x}^{2}  + 2x

b . \: x(2x - 5) \\  \:  = x \times 2x - x \times 5 \\  \:  \:  = 2 {x}^{2}  - 5x

c. \: 2x(3x + 4) \\  \:  = 2x \times 3x + 2x \times 4 \\  \:  \:  = 6 {x}^{2}  + 8x

d. \: 6x(x - 2) \\  \:  \:  = 6x \times x  - 6x \times 2 \\  \:  \:  = 6 {x}^{2}  - 12x

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0
3 years ago
True or false Please
nevsk [136]

respuesta:primero verdadero

segundo : no

7 0
2 years ago
Dont understand please help easy 20pts
nlexa [21]

Answer:

The answer is G. y=2x-2

Step-by-step explanation:

y+6=2(x+2)

First you multiply 2 by what is in the parenthesis

y+6=2x+4

Next you get y by itself by subtracting 6

y=2x+4-6

Simplify

y=2x-2

4 0
3 years ago
Please help me!
Taya2010 [7]

Answer:

  • x = 12
  • Side = 23 units

Step-by-step explanation:

<u>STU is an equilateral triangle. And:</u>

  • ST = 2x - 1
  • SU = 5x - 37
  • TU = x + 11

<u>All sides are equal. Then take one pair and solve for x:</u>

  • 2x - 1 = 5x - 37
  • 3x = 36
  • x = 12

<u>Substitute x to find the side length:</u>

  • 2x - 1 = 5x - 37 = x + 11 = 23
8 0
3 years ago
Express in the form 1 : n give n as a simplifeid fraction 8 : 6​
Paladinen [302]

Answer:

So, Simplified fraction of 8:6 is 4:3.

3 0
2 years ago
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