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Mkey [24]
3 years ago
12

Help me with this question

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

There is nothing there

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Question: 1/10 what is the equivalent percent and decimal?
GrogVix [38]

Answer:

Decimal: 0.1

Percent: 10%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Hilary Unraveled 3.0 centimeters of ribbon then continued to unravel 1.5 more centimeters. Which horizontal number line could be
Snezhnost [94]

<u>Answer:</u>

The horizontal number line that could be used to show number of centimeters of ribbon Hilary unraveled is 3cm to 4.5cm

<u>Explanation:</u>

Given that Hilary has already unraveled 3.0 centimeters of ribbon and then continues to unravel 1.5 more.

So starting will be 3.0 cm and maximum ribbon unravelled will be equal to 4.5cm so the horizontal number line that could be used would be from 3cm to 4.5cm including both fractional and integral values.

6 0
3 years ago
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What is the solution set for the following equation?<br> x² = 16
Alisiya [41]

Answer:

\{4,-4\}

Step-by-step explanation:

~~~~x^2 = 16\\\\\implies x = \pm\sqrt{16}\\\\\implies x =\pm 4\\\\\implies x = 4 ,~ x = -4

6 0
2 years ago
Read 2 more answers
#22 #24 and #26 HELP
Grace [21]
#22)
4(t - 8) + 20 = 5
Distribute the 4.

4t - 32 + 20 = 5
Combine like terms.

4t - 12 = 5
Add 12 to both sides.

4t = 17
Divide both sides by 4.

t = 4.25


#24)
17 = -5(3 + w) + 7
Distribute the -5.

17 = -15 - 5w + 7
Combine like terms.

17 = -8 - 5w
Add 8 to both sides.

25 = -5w
Divide both sides by -5.

w = -5


#26)
9 = -(r - 5) + 11
Distribute the -.

9 = -r + 5 + 11
Combine like terms.

9 = -r + 16
Subtract 16 from both sides.

-7 = -r
r = 7
7 0
3 years ago
How do I do this problem?
Ber [7]

Answer:

Step-by-step explanation:

∠CFE is made up of ∠3 + ∠4; therefore,

∠3 + ∠4 = 74

∠BFD is made up of ∠2 + ∠3; therefore,

∠2 + ∠3 = 103

∠BFE is made up of ∠2 + ∠3 + ∠4; therefore,

∠2 + ∠3 + ∠4 = 136

and we are looking for the measure of ∠CFD which is ∠3.

Begin by using the fact that ∠3 + ∠4 = 74 and sub that into ∠BFE:

∠BFE      =      136 and

∠2 + (∠3 + ∠4) = 136 and

∠2 + 74 = 136 so

∠2 = 62

Now use that in ∠BFD since

∠BFD    =      103 and

∠2 + ∠3 = 103 and

62 + ∠3 = 103 so

∠3 = 41

6 0
3 years ago
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