9514 1404 393
Answer:
A. G(x) = ∛(x -1) +1
Step-by-step explanation:
The transformation f(x-h) +k represents a translation (right, up) by (h, k) of the parent function f(x).
Your translation of f(x) = ∛x by (1, 1) will give you the function ...
G(x) = ∛(x -1) +1
We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
Answer:
| a - b | < length of third side < a + b
Step-by-step explanation:
Visualize the two given sides of the triangle (let's call then a and b), joined at the vertex of the triangle, and forming an angle. We can join the other free end of these two segments, with another segment whose length would vary according to how tiny or large the angle is. We can spread the aperture of the angle they form as much as we can just below (not reaching this angle measure, because in such case, there will be no triangle of tangible area. In such case, the length of the joining segment will be limited by the addition of the two sides:
length of third side < a + b
In the case the aperture of the angle formed by the two given sides is diminished as much as possible to still form a measurable triangle, the angle has to be just larger than zero, and in such case, the segment joining the other to ends of a and b would be just larger than the absolute value of the difference between a and b:
length third side > | a - b|
These are the two extreme cases, and the length of the third side must be within these limits.
The answer is C
negative times negative is equals to positive
Answer:
3/4w
Step-by-step explanation:
3/4 ÷w = 3/4 × 1/w = 3/4w