Please help with this geometry question

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

Answer:

5894.82 ft^3

Step-by-step explanation:

We have to split the figure into two parts and then find the volume of both and add. The figure is split into a cylinder and hemisphere. The volume of the cylinder is 4823.04 ft^3 because the formula to find the volume of a cylinder is pi(r^2)h. The volume of the hemisphere is 1071.78 ft^3. Now, we have to add those volumes to get our final answer. 4823.04 + 1071.78 = 5894.82.

You might be interested in

M is the centroid (center of gravity) of △ABC, line k goes thru M and intersects AB and AC . The distances of the vertices B and

lana [24]

Answer:

Step-by-step explanation:

The midpoint of BC will be a distance from line k that is the average of the distances of B and C: (17+13)/2 = 15. Call that midpoint P. We know distance MP is half of distance MA. This same relationship will hold with respect to the distances from P and A to any line through M. That is, the distance from line k (through M) is twice the distance from P to line k: 30 units.

5 0

4 years ago

Three equals parentheses five squared 1/2 parentheses you parentheses X squared 1/2

Aliun [14]

Answer:

Can you give me a picture of the question? Or be more specific?

3 0

3 years ago

The question is in the picture.

bogdanovich [222]

Just download photomath bro, does everything for you.

3 0

3 years ago

The distance between the paralled lines 3x + 4y +15 = 0 and 3x + 4y -10 = 0 is equal to: pls help ASAP

Delvig [45]

Answer:

5 units

Step-by-step explanation:

Please see attached pictures for the full solution.

(This distance is the perpendicular distance between the 2 parallel lines, which is the shortest distance between them.)

6 0

3 years ago

Reasoning triangle $abc$ has a perimeter of $12$ units. the vertices of the triangle are $a(x,\ 2),\ b(2,-2)$ , and $c(-1,\ 2)$

OlgaM077 [116]

hmmm let's find the distance between B and C first off.

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{-1}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{(~~-1 - 2~~)^2 + (~~2 - (-2)~~)^2} \implies BC=\sqrt{(-1 -2)^2 + (2 +2)^2} \\\\\\ BC=\sqrt{( -3 )^2 + ( 4 )^2} \implies BC=\sqrt{ 9 + 16 } \implies BC=\sqrt{ 25 }\implies BC=5$

hmmm if BC is that much, then AB + AC = 7, since AB + AC + BC = 12 which is the perimeter, Check the picture below.

6 0

2 years ago