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2 years ago

Find the circumference of the circle below to the nearest tenth Use 3.14 for a

Mathematics

1 answer:

AnnyKZ [126]2 years ago

8 0

Answer:

125.6

Step-by-step explanation:

all you have to do is multiple the 3.14 with 40 cm to get 125.6 cm

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Nandini makes 'halwa' one evening and divides it into four equal portions for her family of four. However, just as they are abou

Ahat [919]

Answer:

Step-by-step explanation:

We know that when there are four people, then each person gets 25% of the halwa. However, when the fifth person comes, they have everyone including the guest get 20% of the halwa. In this way, the original four people are losing 5% of their halwa in order for the fifth person to get his piece

4 0

3 years ago

What is 1.4335 in standard form

stich3 [128]

Answer:

-1.4335

Step-by-step explanation:

8 0

3 years ago

How do I subtract fractions? Please explain step by step to get marked!

Mashutka [201]

Answer:

Explained below :)

(I tried my best, sorry if it doesn't make sense.)

Step-by-step explanation:

Example: 1/4 - 1/8= ?

1: Find the common denominator (bottom number)

2: If the common denominator is 8 then you multiply 1/4 by 2/2 to get the denominator of 8. If you needed then you can multiply the other fraction to get the same denominator.

3: Once you get multiply that then you get 2/8 -1/8.

4: Subtract the numerator (top number) 1

5: Keep the numerator (8)

6: Your answer would be 1/8

7 0

2 years ago

How do you work this problem? 5 - 2x = 0

ss7ja [257]

Answer:

x = 5/2

Step-by-step explanation:

Isolate x by adding 2x to both sides, obtaining: 5 - 2x + 2x = 2x. Then 5 = 2x, and dividing both sides by 2 results in x = 5/2.

6 0

3 years ago

Any 10th grader solve it <br>for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$