Answer:
1,500 tickets in total (375 adult tickets and 1,125 children tickets)
Step-by-step explanation:
Let x be the number of adult tickets sold.
Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.
Children tickets were three dollars, so 3x children tickets cost 
Adult tickets were seven dollar, so x adult tickets cost 
The school sold $6000 worth of tickets.
Hence,

The answer to your question is C.
Answer:
The area of the circle is 
Step-by-step explanation:
we know that
The area of a circle is equal to

we have
-----> the radius is half the diameter
substitute the value


1.) Start by figuring out what the 4x3 grid would look like. In this grid, we have 12 boxes (4 x 3 = 12).
2.) Now let's calculate 25% of 12. When changing a percent to a decimal, simply move the decimal point over to the left two places. So then 25% = .25 when written as a decimal. Multiply 25 x 12. 25% of 12 equals 3.
3.) Now your grid would have 3 boxes shaded in. I put two examples of this in the attached image. However, your boxes can be shaded in anywhere in the grid, as long as only 3 of them are shaded in!
If you have |a|=b, solve a=b and a=-b
so
|-4+5x|=16
so solve
-4+5x=16 and -4+5x=-16
add 4 to both sides
5x=20 and 5x=-12
divide both sides by 5
x=4 and x=-12/5
the 2 solutions are x=-12/5 and x=4