Multiply: (3x-4)(2x-5)
This comes out to 6x^2 - 15x - 8x + 20
Combine the x terms and you'll be done.
Answer:
the only thing you need to do is to divide the speed with the distance
Answer:
I want to show you how to do this as well, the formula you are working with is a^2+b^2=c^2
Step-by-step explanation:
1.) 8^2+b^2=12^2
64+b^2=144
subtract 64 from both sides
b^2=80
take the square root of 80 and you get
b= 8.9
if you need more help on this let me know, I am going to list the other answers now because to do it all and show work on here is a lot of typing, all of which I will do if you do not understand the first example. Also the c value can ONLY BE THE HYPOTENUSE VALUE. The hypotenuse is the longest side of the triangle. For example, 12 would be the C value on number one and in number two it would be 15.
2.) 14.5
3.) 10.3
4.) 18.8
5.) 8
6.) 15
Hello there!
From that amount of information, you can't get a numerical value for the answer.
Hope This Helps You!
Good Luck :)
Answer:If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is 1/6.
If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is 3/6 = 1/2
Step-by-step explanation:For example, when a die is rolled, the possible outcomes are 1, 2, 3, 4, 5, and 6. In mathematical language, an event is a set of outcomes, which describe what outcomes correspond to the "event" happening. For instance, "rolling an even number" is an event that corresponds to the set of outcomes {2, 4, 6}. The probability of an event, like rolling an even number, is the number of outcomes that constitute the event divided by the total number of possible outcomes. We call the outcomes in an event its "favorable outcomes".