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ASHA 777 [7]
3 years ago
8

2x+4x=3x+1 how do you do this

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
On the left side of the equation, you have like terms : 2x and 4x
That means that you can combine them

2x+4x=3x+1

6x=3x+1

Now, since the 3x is on the other side of the equation, you have to perform the opposite operation by subtracting 3x on both sides of the equation:

The 3x's will cross out on the right side of the equation

3x-3x=0x=0

On the left side:

6x-3x=3x

SO, now the equation looks like:

3x=1

Now, to get x by itself, perform the opposite operation by dividing 3 on both sides of the equation:

The 3's will cross out on the left:

3x ÷ 3 = 1x = x

On the right:

1 ÷ 3 = 1/3

x=1/3
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Answer:

For right angle triangle,

we use Pythagoras theorem that is:

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For question 1:

c = ?

a = 40

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putting them in formula,

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c = ?

a = 12

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putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

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putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

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c = 37

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putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

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