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zheka24 [161]
3 years ago
10

Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18

Mathematics
1 answer:
enot [183]3 years ago
8 0

Answer:

2y - 3x = -15

Step-by-step explanation:

Slope of the line 4x + 6y = 1 is as shown below;

Rewrite in slope intercept form;

6y = -4x+1

y = -4x/6 + 1/6

y = -2x/3 + 1/6

mx = -2/3x

m = -2/3

The slope of the line perpendicular M = -1/(-2/3)

M = 3/2

Get the x and y intercept of 2x+3y = 18

x intercept occurs when y  = 0

2x + 0 = 18

x= 18/2

x = 9

y intercept occurs when x  = 0

0 + 3y = 18

3y= 18

y = 18/3

y = 6

The line passes through the point (9,6)

Write the equation in point slope form

y - y0 = m(x-x0)

y - 6  = 3/2(x-9)

2(y-6) = 3(x-9)

2y - 12 = 3x - 27

2y - 3x = -27 + 12

2y - 3x = -15

This gives the required equation

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3 years ago
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Read 2 more answers
Which of the following is not a factor of x^3 – 3x^2 – 4x + 12?
Slav-nsk [51]

Answer:

c. (x + 3)

Step-by-step explanation:

using factor theorem

if x - 3 is a factor then p(a) = 0

p(a)= x^3 - 3x^2 - 4x + 12

a.(x-3)

p(3) = (3)^3 - 3(3)^2 - 4(3) + 12

= 27 - 27 - 12 + 12

= 0

therefore x-3 is a factor

b.(x + 2)

p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12

= -8 -12 + 8 + 12

,= 0

therefore x + 2 is a factor

c.(x + 3)

p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12

= -27 -27 + 12 + 12

= -30

therefore x + 3 is not a factor

d.(x-2)

p(2) = (2)^3 - 3(2)^2 - 4(2) + 12

= 8 -12 - 8 + 12

= 0

therefore x - 2 is a factor

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3 years ago
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Answer:

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