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Elis [28]
3 years ago
14

Rationalize the denominator of square root of negative 49 over open parentheses 7 minus 2 i close parentheses minus open parenth

eses 4 plus 9 i.
a) -49+2i/-40
b)49+21i/58
c)77+21i/-2
d)-77+21i/130

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

The answer is the option d, which is: d) \frac{-77+21i}{130}

The explanation for this problem is shown below:

1. Smplify the denominator and rewrite the numerator in this form:

\frac{7i}{7-2i-4-9i} \\\frac{7i}{3-11i}

2. Multiply the denominator and the numerator by the conjugated (3+11i) and simplify the expression, as following:

\frac{7i(3+11i)}{(3-11i)(3+11i)} \\ \frac{21i+77i^{2}}{121+9}  \\ \frac{-77+21i}{130}

3. As you can see, you obtain the expression shown in the option mentioned above.

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Which expressions are equivalent to the one below? Check all that apply.
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log (1/3)

Step-by-step explanation:

log  \: 2 - log \: 6 \\  \\  = log \frac{2}{6}  \\  \\  = log \frac{1}{3}

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Sarris daily tips this work week were $43, $32, $65, $88, $50 and $72. Is Sarah correct in thinking that the mean accurately rep
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The answer is A.

Add all the number values together and then divide it by the number of values you have: 43+32+65+88+50+72=350
350/6=58.33
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Select the correct locations on the graph. select the lines that represent functions.<br>​
sleet_krkn [62]

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right side, bottom. curve

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A number decreased by 4 is greater than 13 solve pls
eimsori [14]

Answer:  

Year 10 Interactive Maths - Second Edition

Problem Solving

Linear equations are often used to solve practical problems that have an unknown quantity. We use a suitable pronumeral to represent the unknown quantity, translate the information given in the problem into an equation, and then solve the equation using the skills acquired earlier in this chapter.

Example 11

If a number is increased by 8, the result is 25. Find the number.

Solution:

Let x be the number.  Increasing x by 8 gives x + 8, which we are told is 25.  Therefore, x + 8 = 25.  Subtract 8 from both sides to find x = 17.  So, the number is 17.

Step-by-step explanation:

I hope this helps!!!

4 0
2 years ago
Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e
Bingel [31]
Assuming the series is

\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}

The series will converge if

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|

We have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|

So the series will certainly converge if -1, but we also need to check the endpoints of the interval.

If x=1, then the series is a scaled harmonic series, which we know diverges.

On the other hand, if x=-1, by the alternating series test we can show that the series converges, since

\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0

and is strictly decreasing.

So, the interval of convergence for the series is -1\le x.
6 0
3 years ago
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