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AnnyKZ [126]
3 years ago
14

Several million lottery tickets are sold, and 21% of the tickets are held by men. Suppose you select a random sample of people a

nd let X represent the number of people in your sample for which are men with winning tickets. What type of random variable is X?
hypergeometric

Bernoulli

poisson

uniform
Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

hypergeometric

Step-by-step explanation:

For each winning ticket, there are only two possible outcomes. Either it is held by a men, or it is not.

There is a set number of X, and as the number of winning tickets decrease, the probability of a winning ticket being held by a men can decrease or increase. This is a characteristic of the hypergeometric distribution.

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The elevation of city A is 60 feet above sea level; the elevation of city C is 12 feet above sea level. The elevation of city D
Likurg_2 [28]

A) 1/2*12 = 6 ft above sea level

B) Because City D is 1/2 of 6, it cannot be negative because we are not multiplying anything by a negative number.

3 0
3 years ago
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The table of values shown below represents a linear function. Which of these points could also be an ordered pair in the table,
Gennadij [26K]

Answer:

<h3>B</h3>

Step-by-step explanation:

not sure if i am right but go off process of elimination

A is a not it to get slope you need to do Y=Mx+b because the slope should be 1.3 and if you get the deciml form of 3 over 9 it would be 0.75

and if you do same process on all of then you will see it is B

4 0
3 years ago
1. Which number does NOT represent a whole number?<br> A 25<br> B 13<br> С<br> 150<br> 3<br> D 3.5
raketka [301]
D doesn’t represent a whole #
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3 years ago
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Translate this sentence into an equation.
Shalnov [3]

Answer:

m - 11 = 44

Step-by-step explanation:

Breaking the phrase down...

"The difference of Malik's height and 11" - this indicates subtraction.

m - 11

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'= 44'

The equation should be:

m - 11 = 44

Hope this helps.

6 0
3 years ago
~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
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