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asambeis [7]
2 years ago
6

Solve the following using completing the square method :

Mathematics
1 answer:
Lesechka [4]2 years ago
7 0

Answer:

1. is 3843

2. is 4903

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In the diagram,
forsale [732]

Answer:

Probability that the measure of a segment is greater than 3 = 0.6

Step-by-step explanation:

From the given attachment,

AB ≅ BC, AC ≅ CD and AD = 12

Therefore, AC ≅ CD = \frac{1}{2}(\text{AD})

                                  = 6 units

Since AC ≅ CD

AB + BC ≅ CD

2(AB) = 6

AB = 3 units

Now we have measurements of the segments as,

AB = BC = 3 units

AC = CD = 6 units

AD = 12 units

Total number of segments = 5

Length of segments more than 3 = 3

Probability to pick a segment measuring greater than 3,

= \frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}

= \frac{3}{5}

= 0.6

4 0
3 years ago
Jon ran 4 miles in 35<br> minutes. How long did it<br> take him to run a mile
sesenic [268]

Answer:

35/4 minutes per mile

Step-by-step explanation:

rate = time/distance, therefore the answer is 35/4

4 0
3 years ago
In the diagram below, value of x is: <br><br> A. 11 <br><br> B. 55<br><br> C. 5<br><br> D. 35
koban [17]
Sum of complementary angles = 90
so
5x + 35 = 90
5x = 90 -35
5x = 55
x = 11

answer is A. 
x = 11
3 0
3 years ago
If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.
Nadya [2.5K]

Answer:

\dfrac{1}{6}.

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : S=\{1,2,3,4,5,6\}

Number is greater than 3 : A=\{4,5,6\}

Number is odd : A=\{1,3,5\}

Number greater than 3 and an odd number : A\cap B=\{5\}

It is conclude that,

n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1

The probability of getting a number greater than 3 and an odd number is

P=\dfrac{n(A\cap B)}{n(S)}

P=\dfrac{1}{6}

Therefore, the required probability is \dfrac{1}{6}.

4 0
3 years ago
Which graph shows a proportional relationship ?
morpeh [17]
It's graph A because it going threw the and has a pattern.
4 0
3 years ago
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