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3 years ago

What is the value of the expression? 32+[4×(15÷3)]−5

Mathematics

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

Step-by-step explanation:

32+[4×(15÷3)]−5

At first we have to apply "BODMAS" rule. According to the rule, we will work 1st bracket.

Hence,

32+[4×5]−5

Then, we will take 3rd bracket into consideration,

32+20−5

Then, we will use addition from the BODMAS rule-

52 - 5

Finally, subtracting 5 from 52, we can get

= 47

The value of the expression is 47.

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Answer:

(a) $y=x^2-2x-8$

(b) $y= -\dfrac12x^2+4x-6$

Step-by-step explanation:

(a) From inspection of the graph, the x-intercepts (where $y = 0$ ) are at

$x = -2$ and $x =4$ .

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--------------------------------------------------------------------------------------------------

(b) From inspection of the graph, the x-intercepts (where $y = 0$ ) are at

$x = 2$ and $x =6$ .

Therefore $y = a(x -2)(x - 6)$ where $a$ is some constant

The y-intercept is at (0, -6)

Expanding the equation:

$y = a(x -2)(x - 6)$

$\implies y = a(x^2-6x-2x+12)$

$\implies y= ax^2-8ax+12a$

Therefore, 12a is the y-intercept

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$-6 = 12a \implies a = -\dfrac12$

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$\implies y= (-\dfrac12)x^2-8(-\dfrac12)x+12(-\dfrac12)$

$\implies y= -\dfrac12x^2+4x-6$

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