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3 years ago

What is 2/1 divided by 1 6/7?

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

<span>What is 2/1 divided by 1 6/7?
</span>answer would be 0.9

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Rebecca needs 10 1/2 yards of fabric to make a quilt. She has one piece of fabric that is 2 1/2 yards and another piece of fabri

nikdorinn [45]

Answer: 3 3/4 yards. I think.

Step-by-step explanation: 10 1/2=10 2/4 2 1/2=2 2/4

10 2/4 - 2 2/4= 8. 8= 7 4/4. 7 4/4 - 4 1/4= 3 3/4.

7 0

3 years ago

Neil has 3 partially full cans of white paint.They contain 1/3 gallon,1/5 gallon,and 1/2 gallon of paint.About how much paint do

Wittaler [7]

Answer:

less than 1 1/2 gallons

Step-by-step explanation:

1/3 + 1/6 = 1/2, so the sum of the three cans is more than 1 by the difference between 1/5 and 1/6. That difference is 1/30 gallon. The sum is 1 1/30 gallons, which is less than 1 1/2 gallons.

A suitable common denominator is 2·3·5 = 30. Then the sum of the fractions is ...

1/3 + 1/5 + 1/2

= 10/30 + 6/30 + 15/30

= 31/30 = 1 1/30 . . . . . less than 1 1/2

In decimal, 1/3 ≈ 0.333, 1/5 = 0.200, 1/2 = 0.500, so the sum is ...

0.333 +0.200 +0.500 = 1.033

which is less than 1.5.

4 0

4 years ago

A bucket contains 40 red balls, 25 black balls, and 35 white balls. Two balls are drawn at random. What is the probability that

Lyrx [107]

Answer:

$Probability = \frac{1}{5}$ or $Probability = 0.2$

Step-by-step explanation:

Given

$Black = 25$

$White = 35$

$Red = 40$

Required

Determine the probability of selecting Black and Red

First, we need to calculate the number of red and black balls

The probability is calculated as thus:

$Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)$

Convert to mathematical expressions

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$

Solve for each probaility;

$P(Black) = \frac{Black}{Total} = \frac{25}{100}$

$P(Red) = \frac{Red}{Total} = \frac{40}{100}$

So, we have:

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$ $Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]$

$Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]$

$Probability = [\frac{1}{10}] + [\frac{1}{10}]$

$Probability = \frac{1+1}{10}$

$Probability = \frac{2}{10}$

$Probability = \frac{1}{5}$

$Probability = 0.2$

7 0

3 years ago

This is rlly easy but Im to lazy to do it- I mark brainliest.

kkurt [141]

Answers:

A. 6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78 seats in total

B. 6 Large taxis = $498 + 9 Small taxis = $450 498+450= $948

C. 5 Large taxis and 10 Small taxis

Step-by-step explanation:

A. 6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78 seats in total

If I did 8 small taxis the total number of seats would be 74, so I did one small taxi more to make it fair. There would be seats for everyone but 3 seats extra

B. 6 Large taxis = $498 + 9 Small taxis = $450 498+450=948

C. 5 Large taxis and 10 Small taxis

While the more small taxis there are, the more cheaper it is for Max but the less seats there would be for 75 people, So I did 1 more small taxi and 1 less large taxi.

The total number of seats now is 75 seats which is perfect amount for 75 people

So the total cheaper cost would $915 while still maintaining a fair amount of seats which is 75

3 0

3 years ago

Which of the following is true?

gtnhenbr [62]

Answer:

C..... I think it is a answer

6 0

3 years ago