What is the area of the quadrilateral with vertices at (1, 0), (2, 0), (2, 5), and (1, 5)?
2 answers:
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A = length x width
15,000 = (w + 30) x w
15,000 =
+ 30w
0 = + 30w - 15,000
Use quadratic formula to find that w= -15 + or - 5
. Because distance cannot be negative, the width is -15 + 5meters or approximately 108.39 meters. This means that the length is approximately 138.39 meters.
15,000 = (w + 30) x w
15,000 =
0 =
Use quadratic formula to find that w= -15 + or - 5