Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
Step-by-step explanation:
Alright so, we need need to lay down the clues we were given
●Ratio of the seats= 2:5
● No.of seats in the circle
●Fraction of seats occupied for the stalls
Now, let us take a closer look at the ratio;
<em>C</em><em>:</em><em> </em><em>S</em><em> </em><em> </em><em>Total</em>
2:5 7
As we can see, the number of parts for the circle is 2 parts.
So ,
2 parts = 528 seats
1 part= 528/2= 264 seats
5 parts= 1 320 seats
7 parts= 264 × 7 = 1 848
Finally,
We can now find the seats occupied by the stalls,
2/3 × 1 320
= 880 seats
Seats of circle + Seats of stall
= 528 + 880= 1408
Percentage Occupancy
=
1408/1 848 × 100
Note: The answer will come in decimal numbers.
It will be,
76.1904761905
or
76.19%
ANSWER
Answer:
8
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Hope this helps!
Refer to the figure shown below.
x = the width of the rectangle (meters)
y = the height of the rectangle (meters(
The fencing for the perimeter of the rectangle costs $30 per meter.
The two inner partitions cost $25 per meter.
The total cost of the fencing is
C = 2(x+y)*$30 + 2y*$25
= 60(x+y) + 50y
= 60x + 110y
Because the amount available to spend is $600, therefore
60x + 110y = 6000
or
6x + 11y = 600
That is,
y = (600 - 6x)/11 (1)
The area is
A = x*y (2)
Substitute (1) into (2).
A = (x/11)*(600 - 6x) = (1/11)*(600x - 6x²)
To maximize A, the derivative of A with respect to x is zero.
That is,
600 - 12x = 0
x = 600/12 = 50
From (1), obtain
y = (1/11)*(600 - 6*50) = 300/11 = 27.273
Because the second derivative of A with respect to x is negative, x=50, y = 27.273 will yield the maximum area.
The maximum area is
50*27.273 = 1363.64 m² = 1364 m² (nearest integer)
Answer: 1364 m² (nearest integer)