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3 years ago

What's y=-4+15 in standard form

Mathematics

1 answer:

kotykmax [81]3 years ago

5 0

Answer:

y=1.1×10¹

Step-by-step explanation:

y=-4+15

y=11

y=1.1×10¹

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Find the error & find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=

Art [367]

Answer:

Error: $lnx^2=ln 3x$ not $ln\frac{3x}{0}$

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given: $2ln x=ln(3x)-[ln9-2ln(3)]$

$lnx^2=ln(3x)-[ln9-ln3^2]$

Using the formula

$alog b=logb^a$

$lnx^2=ln(3x)-[ln9-ln9]$

$lnx^2=ln(3x)-0$

$lnx^2=ln(3x)$

$x^2=3x$

$x^2-3x=0$

$x(x-3)=0$

Therefore, x=0 and x=3

But last step in the given solution

$lnx^2=ln\frac{3x}{0}=\infty$

It is wrong this property is used when

$log m-log n$ then

$log\frac{m}{n}$

Hence, the student wrote $lnx^2=ln\frac{3x}{0}$ instead of $lnx^2=ln3x$ and solution is given by

x=0 and x=3

4 0

4 years ago

A theatre has the capacity to seat people accross two levels, the circle and the stalls.

LenKa [72]

Step-by-step explanation:

Alright so, we need need to lay down the clues we were given

●Ratio of the seats= 2:5

● No.of seats in the circle

●Fraction of seats occupied for the stalls

Now, let us take a closer look at the ratio;

C: S Total

2:5 7

As we can see, the number of parts for the circle is 2 parts.

So ,

2 parts = 528 seats

1 part= 528/2= 264 seats

5 parts= 1 320 seats

7 parts= 264 × 7 = 1 848

Finally,

We can now find the seats occupied by the stalls,

2/3 × 1 320

= 880 seats

Seats of circle + Seats of stall

= 528 + 880= 1408

Percentage Occupancy

1408/1 848 × 100

Note: The answer will come in decimal numbers.

It will be,

76.1904761905

76.19%

ANSWER

3 0

3 years ago

What is the range? The range is 2 3 4 4 5 6 7 8. 9 10

ale4655 [162]

Answer:

Step-by-step explanation:

7 0

3 years ago

The following table represents a linear function. Find the y-intercept. y-intercept

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

You have $6000 with which to build a rectangular enclosure with fencing. The fencing material costs $30 per meter. You also want

Roman55 [17]

Refer to the figure shown below.
x = the width of the rectangle (meters)
y = the height of the rectangle (meters(

The fencing for the perimeter of the rectangle costs $30 per meter.
The two inner partitions cost $25 per meter.

The total cost of the fencing is
C = 2(x+y)*$30 + 2y*$25
= 60(x+y) + 50y
= 60x + 110y

Because the amount available to spend is $600, therefore
60x + 110y = 6000
or
6x + 11y = 600
That is,
y = (600 - 6x)/11 (1)

The area is
A = x*y (2)

Substitute (1) into (2).
A = (x/11)*(600 - 6x) = (1/11)*(600x - 6x²)

To maximize A, the derivative of A with respect to x is zero.
That is,
600 - 12x = 0
x = 600/12 = 50
From (1), obtain
y = (1/11)*(600 - 6*50) = 300/11 = 27.273

Because the second derivative of A with respect to x is negative, x=50, y = 27.273 will yield the maximum area.

The maximum area is
50*27.273 = 1363.64 m² = 1364 m² (nearest integer)

Answer: 1364 m² (nearest integer)

5 0

3 years ago