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Tomtit [17]
3 years ago
12

Solve for x. 10x^2=29x-21 does anyone know this

Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0
10x^2=29x-21 \\
10x^2-29x+21=0\\
\Delta=(-29)^2-4\cdot10\cdot21=841-840=1\\
\sqrt{\Delta}=\sqrt1=1\\
x_1=\frac{-(-29)-1}{2\cdot10}=\frac{28}{20}=\frac{7}{5}\\
x_2=\frac{-(-29)+1}{2\cdot10}=\frac{30}{20}=\frac{3}{2}\\
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