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3 years ago

Does the mapping diagram represent a function? Why or why not?

Mathematics

1 answer:

fredd [130]3 years ago

4 0

Answer:

i realy dunno

Step-by-step explanation:

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Simplify: x(x-2)-3x(2x-1)

julsineya [31]

Answer:

-5x^2 +x

Step-by-step explanation:

x(x-2)-3x(2x-1)

Distribute

x^2 -2x -6x^2 +3x

Combine like terms

-5x^2 +x

4 0

3 years ago

Read 2 more answers

The mean score on a physics test was 75 points. Amy’s score was 67 points, which was 2 standard deviations below the mean. What

Norma-Jean [14]

Answer:

Its 16

Step-by-step explanation:

i had the same question and this was the answer on the unit test

7 0

2 years ago

IF P(Q AND R) =0.2 ANDP(R)=0.8 FIND P(Q/R)

expeople1 [14]

P(Q/R) = P(Q and R)/P(R) = 0.2/0.8 = 0.25

3 0

3 years ago

Which is greater 5/6, 3/4, or 7/10?

andriy [413]

5/6 = 50/60
3/4 = 45/60
7/10 = 42/60

So as we can see 5/6 is the greatest

4 0

3 years ago

Find the volume of the solid bounded by z = 2 - x2 - y2 and z = 1. Express your answer as a decimal rounded to the hundredths pl

butalik [34]

Answer:

The answer is " $(\frac{\pi}{2})$ ".

Step-by-step explanation:

$z = 2 - x^2 - y^2.........(1) \\\\z = 1.............(2)$

Let add equation 1 and 2:

Using formula: $x^2+y^2=1 \\\\$

convert to polar coordinates

$r=2$

$\theta \varepsilon (0=\pi)=z\\\\V=\int^{2\pi}_{\theta=0}\int^{1}_{\pi=0}\int^{z_{2}}_{z_1} r \ dr \d \theta\\\\$

$=\int^{2\pi}_{0}\int^{1}_{0} (Z_2-z_1)r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} 1- (-1-x^2-y^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (+1 \pm r^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (-r^3 + r) \ dr \d \theta\\\\=\int^{2\pi}_{0} (-\frac{r^4}{4}+\frac{r^2}{1})^{1}_{0} \d \theta\\\\=\int^{2\pi}_{0} (\frac{1}{4}) \d \theta\\\\=(\frac{2 \pi}{4}) \\\\=(\frac{\pi}{2}) \\\\$

8 0

3 years ago