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Artyom0805 [142]
3 years ago
9

Which animal adapts in goa​

Biology
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

elephant

Explanation:

An important and widely found animal of Indian tropical rainforests is the elephant. It has adapted remarkably to the conditions of this region.

hope it helps

pls mark me as brainliest

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A student wants to view a cell’s mitochondria. Which of the following microscopes would show a mitochondria’s internal structure
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Answer:

Transmission Electron Microscope would show a mitochondria’s internal structure in the greatest detail

Explanation:

The TEM is used to visualise the internal structure of the cells. This works when an electron beam of light passes through the object or the sample, it shows a clear presence of the organelles inside the cell. The TEM uses the energetic electron which provides the morphological as well as compositional and crystallographic features of the cell. Its maximum potential is about 1 nanometre. Among the most powerful microscope for studying the internal organelles of the cell TEM is one.

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2 years ago
A new kind of tulip is produced that develops only purple or pink flowers. Assume that flower color is controlled by a single-ge
Sophie [7]

Answer:

a. purple allele (C) = 0.609, pink allele (c) = 0.391

b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476

Explanation:

Given -

Purple flowers - 847

Pink flowers - 153

The frequency of recessive genotype i.e

q^ 2 = \frac{153}{1000} \\q^ 2 = 0.153\\

Frequency of recessive allele i.e q is equal to

q = \sqrt{0.153} \\q = 0.391

As per hardy Weinberg's first equilibrium equation -

p + q = 1\\p = 1-q\\p = 1-0.391\\p = 0.609

Frequency of purple homozygous species

= p^2\\= 0.609^2\\= 0.371

Number of purple homozygous species = 0.371 * 1000= 371

Number of pink homozygous species = 0.153 * 1000= 153

Heterozygous species is equal to

(1-0.371-0.153)* 1000\\= 0.476 * 1000\\= 476

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