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irakobra [83]
3 years ago
7

Find acute angle between the line 2x+4y=7 and x+2y=5

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

arctan(4/3) ≈ 0.9272

Step-by-step explanation:

On comparing eqⁿ to y = mx + c,

Slope of 2x + 4y = 7 is -2/4 = - 1/2

Slope of x + 2y = 5 is - 1/2

Therefore, if A is the angle b/w them,

A = arctan | (m1 + m2)/(1 - m1m2) |

A = arctan | (-½ - ½)/(1 - ¼) |

A = arctan (4/3)

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so with this to get the 5 to a 10 you have to times it by 2

so you do the same to the 1

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8.2.38<br> Find the value of x.<br> * *<br> (Round to the nearest tenth as needed.)
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6 0
3 years ago
Please explain how you got the answers also please. Thank you :)
Umnica [9.8K]

Answer:

x = -2 —> y = 4

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Step-by-step explanation:

<h3>X= –2</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ - 2}  =(  \frac{2}{1} ) ^{2}  =  {2}^{2}  = 4

<h3>X= 0</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ 0}  =1

<h3>X= 3</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ 3}  =  \frac{ {1}^{3} }{ {2}^{3} } =  \frac{1}{8}

I hope I helped you^_^

7 0
3 years ago
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