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yulyashka [42]
2 years ago
7

Who here watches haikyuu im bo.red and wanna talk about something

Mathematics
2 answers:
gtnhenbr [62]2 years ago
6 0

Answer:

we can talk if you want, and i watch haikyuu too lol (and more animes)

Step-by-step explanation:

emmainna [20.7K]2 years ago
4 0

Answer:

i lovveeee haikyuu. biggest hyperfixation right now (and has been for the past year.)

Step-by-step explanation:

do you have discord? i could add you on there! you can get it on mobile, too, if your school laptop blocks it.

my favorite characters right now are sakusa, atsumu, and kita. i have a lot more, though!

my discord is:

dex (derogatory) # 6129

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Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500dollar sign by selling c box of
hoa [83]

Answer:

$500. 500/2.75= 181 boxes

Step-by-step explanation:

You divide the amount of money by the amonunt of money for each box to find how many boxes you sell to make.

8 0
2 years ago
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Which of the following expressions is equivalent to -5.4 - (2.1 + 1.8)?
Leno4ka [110]
-5.4 - (2.1 + 1.8)=-9.3

So I would say A. Thanks for asking your question today and have a good day on Brainly.com! :)
4 0
3 years ago
Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

compare them away.
4 0
3 years ago
What is the next number in this sequence? 100,10,1___,...
maw [93]
.1 or 1/10
Vote me brainliest!
6 0
2 years ago
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what do u need to find in here?

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