Answer:
Search it
Step-by-step explanation:
Search it up
Answer:
B)
x units
Step-by-step explanation:
Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:
Perimeter of a rectangle = 2 (l + b)
where: l is the length = 12 units and b is the breadth = 8 units. So that:
Perimeter of KMPT = 2 (12 + 8)
= 40 units
Dilating KMPT by a scale factor of
would create K'M'P'T' of dimensions;
× 12 units by
× 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.
Perimeter of K'M'P'T' = 2 (l + b)
= 2(9 + 6)
= 30 units
Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be
× perimeter of KMPT.
Therefore, if the perimeter of KMPT is x units, then;
perimeter of K'M'P'T' =
* x units
=
x units
Answer:


Step-by-step explanation:
please mark me brainliest
The problem ask to find the are of the shaded region of the circle which has a radius of 12cm. The are of the circle is computed as the formula of pie times the square of the radius so the are of the circle would be 452.389 cm2 and the area of the shaded region would be 150.796 cm2^2. I hope you are satisfied with my answer and feel free to ask for more
The answer is (C). All sides and angles of the square is equal. Its diagonals bisect each other and meet at 90°. If two lines are said to meet at 90°, these lines are perpendicular to each other. Therefore, the diagonals of a square is perpendicular to each other