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3 years ago

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If there are 5 chaperones for every 14 kids on the feild trip and there is a total of 152 people on the trip, how many of them a

re adults?

1 answer:

Amanda [17]3 years ago

6 0

Answer:

40

Step-by-step explanation:

Add the 5 to the 14 to get 19 for a total, divide your 19 by 152. You get 8. You then multiply the 5 from the original part by 8 to get 40.

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A landscaper has 10 2/5 cubic yards of peat moss in a truck. If he unloads 2 2/3 cubic yards at the first site and 2 1/4 cubic y

Vikentia [17]

Step-by-step explanation:

The problem bothers on fractions, here we are being presented with mixed fractions.

what we are going to do bascially is to subtract the sum of all the uloaded

peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site

therefore

$10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})$

we then have to convert the mixed fraction to further simplify the problem we have

$\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})$

we then solve the fraction to the right of the negative symbol first

$=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}$

We can now convert to mixed fraction

$=\frac{329}{60}\\\\ =5\frac{12}{25}$

For the third site the remainder is 5 12/25

8 0

3 years ago

Determine if the triangles are congruent. If they are, state how you know.

hram777 [196]

Answer:

1 - SSS

Step-by-step explanation:

We need either two sides one angle, two angles one side, or three sides to prove congruency. In this case we have 3 sides so therefore this is congruent by the SSS theorem.

6 0

3 years ago

Read 2 more answers

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

What equations are equivalent to 3(5x+4)=12x+18

Vladimir79 [104]

Answer:

Step-by-step explanation:

4 0

3 years ago

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NEED ANSWER FAST WILL GIVE BRAINLIEST Object A and Object B are two objects in motion. Given the graph of Object A and the equat

faust18 [17]

By graph of object A the rate of change is estimated at 17/6.
Object B's rate of change is 10/3=20/6.

Comparing object A to object B:
17/6 <20/6

Object B is faster by:
17/6x=20/6
(6/17)(17/6)x=(20/6)(6/17)
x=20/17≈1.18

B)
Object B by a factor of 1.19

Since I made an estimation from graph of object A , my solution is off by. 01 but it is the closest I can get. The solution B is correct.

8 0

3 years ago

Read 2 more answers