The lot costs 5000 dollars.
<u>Step-by-step explanation:</u>
The cost of a House and the lot = $40,000.
Let us assume the cost of lot as 'x'
Given that, The cost of the house is 7 times as much as the lot.
Therefore, The cost of the house= 7x
The cost of both the house and the lot= x + 7x
$40,000 = x + 7x
40,000 = 8x
x = 40,000/8
x = 5,000
The lot costs $5000.
Answer:
He will pay 225 in interest
Step-by-step explanation:
found on quizlet
The two equations would be
32a+50b=14600
10a+40b=7000
To solve, we need to eliminate one variable.... let’s eliminate b
4(32a+50b=14600) —> 128a+200b=58400
-5(10a+40b=7000) —> -50a-200b=-35000
So when we add them together’ we get 78a = 23400
So solve that and a= 300, so class a tickets cost 300 euros each
Substitute a=300 into first equation in the system of equations at the beginning and 32(300)+50b=14600 —> 9600+50b=14600 —> 50b = 5000 or b= 100, so the cost for class b tickets is 100 euros each
Answer:
still need it??
Step-by-step explanation:
