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3 years ago

find the vertex, the equation and axis of symmetry, and the y-intercept of the graph of y=-3x^2-13x+3

Mathematics

1 answer:

stepladder [879]3 years ago

6 0

Answer:

Vertex: (13/6,-133/12)

Axis of symmetry: x=13/6

y-intercept: y=3

Step-by-step explanation:

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3 years ago

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2 years ago

Read 2 more answers

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

7 0

2 years ago

Solve this equation by Euclid's application of areas: x^2 + 12x = 64.

Karolina [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Simplify (2 3/5) divided ( -3 3/4)

Ostrovityanka [42]

Flip over the second fraction

2 3/5= 13/5 ( Multiply the whole number with the denominator, 2*5=10 then add the numerator 10+3=13

-3 3/4= -15/4

13/5 * -4/15= -52/75

Answer :-52/75

4 0

3 years ago