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MakcuM [25]
3 years ago
15

Solve the equation. Graph the solution on a number line. (You don’t have to graph it, I just need the equation answer.)

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
X=4

divide the 5 on both sides
5x=20
x=4
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Please help will give brainliest thank you.
tester [92]

Two events are dependent if the outcome of the first event affects the outcome of the second.

The last answer is the correct one.

5 0
3 years ago
What fraction is equal to 2/5 4/7,4/10,6/9
Julli [10]
4/10 is equal to 2/5 because if you reduce 4/10 you get 2/5 which shows that they are equal.
7 0
3 years ago
What is the greatest number of teams can be formed that have the same amount of boys and girls on each team if they have 54 girl
elena55 [62]

The greatest number of teams can be formed that have the same amount of boys and girls on each team is 6

<em><u>Solution:</u></em>

Given that there are 54 girls and 84 boys

We have to find the greatest number of teams can be formed that have the same amount of boys and girls on each team

So we have to find the greatest common factor of 54 and 84

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

<em><u>Let us find the factors of 54 and 84</u></em>

The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54

The factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

In the above factors list, 6 is the greatest common factor

Then the greatest common factor is 6

So the greatest number of teams can be formed that have the same amount of boys and girls on each team is 6

7 0
4 years ago
Rhada has a 3-pound bag of clay. Her craft project requires 3 ounces of clay for each batch of 5 ornaments. If she uses all of t
konstantin123 [22]

Answer:

80 ornaments

Step-by-step explanation:

3lb times 16oz= 48 oz.

48oz / 3 =  16 batches

o= 16 batches times 5 ornaments=  80 ornaments

80 ornaments.  Someone correct me if im wrong.

6 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
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