Answer:
The squirrel maximum height (h) = 21.125 ft
Step-by-step explanation:
The objective of this question is to determine the squirrel's maximum height.
Given that:
h = -2t² + 9t + 11
Differentiating h with respect to t, we get;

At the time dh/dt = 0, the velocity is maximum
Thus;
-4t = -9
4t = 9
t = 9/4
t = 2.25 seconds
From;
h = -2t² + 9t + 11
h = - 2(2.25)² + 9(2.25) + 11
h = - 10.125 + 20.25 + 11
h = 21.125 ft
5/6 as in five sixths hope this helps!
The answer to (-8) + (-5) = -13
2(3)^3 + 4(3)^2-6(3)
2x 27 + 4x9 - 18
54 + 36 -18
= 72
I assume you want it in slop-intercept form.
y = 3/4x + y-intercept (the graph isn't labeled)
If you just want to find the slope of the graph, it would be 3/4