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snow_tiger [21]

2 years ago

15

There are 3 boxes for green chips and 5 boxes for red chips. each box has the same number of chips in it. if there are a total o

f 16 chips complete the tape diagram showing the number of chips in each box.

1 answer:

Sauron [17]2 years ago

6 0

Answer:

<h2>2 in each box of course</h2>

g= green chips r= red chips

3 boxes of green chips meaning for each box there are <em>2</em> chips so there are 6 green chips. 5 boxes of red chips meaning for each box there are two chips so there are 10 red chips and 6 g + 10r = 16 chips in total

Step-by-step explanation:

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Can someone solve this! Need it done soon

Airida [17]

Answer:

117.5 ft²

Step-by-step explanation:

To find the area of the shaded area, we can find the area of the square, then subtract the areas of the two semicircles.

First, we will find the area of the given square, by using the formula $lw$ , multiplying the length and width. The dimensions of this square are 14×14.

14 · 14 = 196

The area of the square is 196 ft².

We can now find the area of the two congruent half-circles. Since they are identical, we can simply find the area of one circle if it was whole. To find the area of a circle, we'll use the formula $A=\pi r^2$ . With some simple deduction, we can see that the diameter of the circle is 10 ft, so the radius would be 5 ft long. Plug our values into the formula.

A = $\pi$ 5²

We will use 3.14 for $\pi$ .

A = 78.5

The area of both the semicircles is 78.5 ft².

Now, we can subtract.

196 - 78.5 = 117.5

The area of the figure is 117.5 ft².

Good luck ^^

7 0

3 years ago

Determine the projection of w onto u.

irina [24]

Answer:

A.6.2i-4.2 j

Step-by-step explanation:

We are given that

$u=9i-6j$

$v=-3i-2j$

$w=19i+15j$

We have to find the projection of w on to u.

The project of vector a on b

= $\frac{a\cdot b}{\mid b\mid^2}b$

$w.u=(19i+15j)\cdot (9i-6j)=171-90=81$

$\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}$

Using the formula

The projection of w on to u

$=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)$

The projection of w on to u=6.2i-4.2j

Hence, option A is true.

4 0

3 years ago

Read 2 more answers

The price of a desktop computer after discount was $1600 if the discount was 20% what was the original price

Harrizon [31]

Answer:$2,000

Step-by-step explanation:

7 0

3 years ago

The area of a square in square feet is

Sedaia [141]

Answer:

Part 1) The expression for the perimeter is $P=4(25z-3)$ or $P=100z-12$

Part 2) The perimeter when z = 15 ft. is $P=1,488\ ft$

Step-by-step explanation:

Part 1)

we have

$625z^{2}-150z+9$

Find the roots of the quadratic equation

Equate the equation to zero

$625z^{2}-150z+9=0$

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$625z^{2}-150z=-9$

Factor the leading coefficient

$625(z^{2}-(150/625)z)=-9$

$625(z^{2}-(6/25)z)=-9$

Complete the square. Remember to balance the equation by adding the same constants to each side

$625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)$

$625(z^{2}-(6/25)z+(36/2,500))=0$

Rewrite as perfect squares

$625(z-6/50)^{2}=0$

$z=6/50=0.12$ -----> root with multiplicity 2

so

The area is equal to

$A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}$

The length side of the square is $b=(25z-3)$

therefore

The perimeter is equal to

$P=4b$

$P=4(25z-3)$

$P=100z-12$

Part 2) Find the perimeter when z = 15 ft.

we have

$P=100z-12$

substitute the value of z

$P=100(15)-12=1,488\ ft$

4 0

3 years ago

Which expression would be easier to simplify if use the commutative property to change the order of numbers?

Fudgin [204]

Try D then maybe try b

5 0

2 years ago