Balanced reaction for formation of water is ;
2H2 + O2 —> 2H2O
Stoichiometry of H2 to H20 is 2:2
1 mol of any gas occupies a volume of 22.4 L
Therefore it 22.4 L contains 1 mole
Then 1.24 L has -1/22.4 x 1.24 = 0.055 mol
Number of water moles formed = 0.055 mol
Therefore mass of water formed = 0.055 mol x 18 g/mol = 0.99 g of water is formed
(Can I have Brainlist)?
Answer:
2C4H10 + 13O2 —> 8CO2 + 10H2O. Oxidation reaction
8 (4 moles CO2 per mole butane)
Explanation:
could be written C4H10 + 6 1/2 O2 —> 4CO2 + 5H2O
Air on a hot day translates to hot air and air on a cold day translates to cold air. The hot air usually have more energy due to particles being more excited by the heat.
Answer:
d. the conjugate base of the weak acid
Explanation:
The strong base (BOH) is completely dissociated in water:
BOH → B⁺ + OH⁻
The resulting conjugate acid (OH⁻) is a weak acid, so it remains in solution as OH⁻ ions.
By other hand, the weak acid (HA) is only slightly dissociated in water:
HA ⇄ H⁺ + A⁻
The resulting conjugate base (A⁻) is a weak base. Thus, it reacts with H⁺ ions from water to form HA, increasing the concentration of OH⁻ ions in the solution.
Therefore, the resulting solution will have a pH > 7 (basic).
