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seraphim [82]
2 years ago
6

Help me please an thank you

Chemistry
2 answers:
agasfer [191]2 years ago
3 0

Answer:

formula unit

Explanation:

Alex73 [517]2 years ago
3 0
Formula unit is the answer
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What is a gift offered to a god by killing or burning something? Plz answer I’ll give brainlist and 50 points for free
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it is a sacrafice to god so the spirtit can go free

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How many molecules are there in 24 grams of Fe? <br><br> (Please explain how you got the answer)
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1 Answer. SCooke · Stefan V. 1.2×1023 molecules. Hope this helps
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2 years ago
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

4 0
3 years ago
Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% N
olga nikolaevna [1]

Answer:

π = 14.824 atm

Explanation:

wt % = ( w NaCL / w sea water ) * 100 = 3.5 %

assuming w sea water = 100 g = 0.1 Kg

⇒ w NaCl = 3.5 g

osmotic pressure ( π ):

  • π = C NaCl * R * T

∴ T = 20 °C  + 273 = 293 K

∴ C ≡ mol/L

∴ density sea water = 1.03 Kg/L....from literature

⇒ volume sea water = 0.1 Kg * ( L / 1.03 Kg ) = 0.097 L sln

⇒ mol NaCl = 3.5 g NaCL * ( mol NaCL / 58.44 g ) = 0.06 mol

⇒ C NaCl = 0.06 mol / 0.097 L = 0.617 M

⇒ π = 0.617 mol/L * 0.082 atm L / K mol * 293 K

⇒ π = 14.824 atm

7 0
3 years ago
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