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Anna35 [415]
3 years ago
11

Uhhhhhhhhhhhh ............

SAT
2 answers:
juin [17]3 years ago
4 0

Answer:

ummmmmmmmm .........

Explanation:

zheka24 [161]3 years ago
4 0

Answer:

*beatboxes with the uhhhhhhh*

Explanation:

You might be interested in
A sample of 400 racing cars showed that 80 cars cost over $700,000. What is the 99% confidence interval of the true proportion o
Amiraneli [1.4K]
,q=0.8, n=400
(a,b)= *=.2+-(2.576*.02)=(.1485, .2515)
We can say with 99% confidence that the proportion of cars costing over $700,000 is in the interval (.1485, .2515).
Hope this helps!

8 0
3 years ago
a helicopter flies parallel to the ground at an altitude of 1/2 kilometer and at a speed of 2 kilometers per minute. if the heli
Murrr4er [49]

The Pythagoras' theorem and the uniform motion allows to find the answer for the rate of change of distance is

               v = 32.3 m / s

The distance is the length of the segment that a white house wing with the helicopter, this can be found using the Pythagoras' theorem

               R = \sqrt{x^2 + y^2}

Where R is the distance, x is the horizontal distance where the helicopter flies and y is the vertical distance that corresponds to the flight height

y = 500 m

Since the helicopter flies at constant speed, we can use the uniform motion relation

              v_h = \frac{x}{t}

              x = v_ht

Where v_h is the speed of the helicopter and t is the time

We substitute  

                r = \sqrt {(V_h \ t)^2 + y^2}

Kinematics defines velocity as the change of position in the unit of time

            v = \frac{dR}{dt}

           v = \frac{1}{2} \  \frac{2 ( v_h t) v_h}{ \sqrt{(v_h t)^2 + y^2} }

           v = \frac{v_h^2 \ t}{ \sqrt{(v_h t)^2 + y^2} }

This expression is the change in distance as a function of time for a given speed. In the exercise, this speed is requested for a time of one minute, for the helicopter speed of

        v = 2km/min (\frac{1000m}{1km} ) ( \frac{1 min}{60s}) = 33.33 m / s

Let's calculate

            v = \frac{33.33^2 \ 60 }{ \sqrt{ )33.3 \ 60)^2 +500^2} }

         

            v = 32.3 m / s

In conclusion using the Pythagoras' theorem and the uniform motion we can find the answer for the rate of change in distance is

               v = 32.3 m / s

Learn more here: brainly.com/question/343682

4 0
3 years ago
Lethargic : vital :: trite :
Anuta_ua [19.1K]
Lethargic means "sluggish", kind of inactive
Vital means full of energy, lively

So, they are antonyms

So, for the 2nd part of the analogy, you are looking for a antonym to trite

Trite means lacking originality or freshness. Overused. Kind of like a cliche

So, an antonym could be original, unique, innovative
8 0
3 years ago
Como saber cual es mi clave en Brainly
uysha [10]
This is in the wrong category
4 0
4 years ago
The straight line is fitted to the time series when the movements in the time series are
gogolik [260]

Answer:

First the time series figures are plotted on a graph. The points are joined by straight lines. We get fluctuating straight lines, through which an average straight line is drawn. This method is however, inaccurate, since different persons may fit different trend lines for the same set of data.24-Mar-2019

7 0
3 years ago
Read 2 more answers
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