Answer: 13
i got the question wrong and it told me the correct answer . thank me later
Answer:
=−2x^2−9x−10
Step-by-step explanation:
would you like an explantion or are you good
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
Step-by-step explanation:
Rule: If x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
Using that rule, we can see that x+5 is really x-(-5) so k = -5.
Therefore,
p(k) = 0
p(-5) = 0
so the answer is choice D.
