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Ira Lisetskai [31]
3 years ago
10

Determine the equation in Point-Slope Form, Slope-Intercept Form, and Standard form of a line that passes through point (5,1) wi

th a slope of - 2/3. Select the three different answers that are correct.
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

Point-slope equation for line of slope -⅔ that passes through (5, 1):

y-1 = -⅔(x-5)

Rearrange to solve for y:

y = -⅔(x-5)+1

y = -⅔x + 13/3 Slope-intercept form

⅔x + y = 13/3

2x + 3y = 13 standard form

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Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2
Rasek [7]

The factorisation of the given expressions is as follows;

  • a) p²y²– 2py + 1 = (py -1)²
  • b) a²y² -2aby +b² = (ay - b)²

<h3>Factorization using identities</h3>

The given identity is;

  • a²– 2ab + b² = (a – b)²

From the given identity, we can conclude that;

In the expression (a);

  • py represents a in the identity and 1 represents b in the identity.

In the expression (b);

  • ay represents a in the identity and b represents b in the identity.

Hence, the factorised expressions are as represented above.

Read more on factorisation;

brainly.com/question/24371127

8 0
2 years ago
Like terms are terms with the same
melisa1 [442]

Answer:

yes?

Step-by-step explanation:

6 0
4 years ago
A cafeteria sells entrees and additional items. An entree costs $4.75, and each additional item costs $1.25. A customer pays $9.
umka2103 [35]
Hello!

ANSWER:

4 additional items were ordered.

EXPLANATION:

First, subtract the cost of the entree:

9.75 - 4.75 = 5

This means that the customer spent $5.00 on on additional items.
Each additional item costs $1.25. Divide:

5 ÷ 1.25 = 4

6 0
3 years ago
Read 2 more answers
Help I just want to know if this is cos, sin, or tan?<br><br> (This is geometry)
vova2212 [387]

Answer:

it's cosine

Step-by-step explanation:

cos45° = x/17

7 0
3 years ago
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F(x)=x^3+8x-19 ,show that the equation f(x)=0 has one real root
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1) Find whether the function, f(x) has a local or absolute maximum or minimum.

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Maximum or minimum => f '(x) = 0 => 3x^2 + 8 = 0 => 3x^2 = -8

Which has not a real solution because x^2 is always positive.

Then there is not maximum or minimum.

Then that function is or increasing or decreasing in all the domain and it can have maximum one real root.

Yet we have to show if there is one root or none root.

if you make x = 1 you find f(x) = 1^3 + 8(1) -19 =  1 +8 - 19 = -10

If you make x =2, you find f(x) = 2^3 + 8(2) -19 = 8 + 16 - 19 = 5

Then f(x), given that it is continuos, will have a zero between x =1 and x = 2, which corresponds to the only root of the function.
3 0
3 years ago
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