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Molodets [167]
3 years ago
8

Ronnie, Bobby, and Mike are singers from the group New Edition. They are raising money for studio time. Ronnie raised $30 more t

han Mike, and Bobby raised $12 less than Ronnie. They collected $432 in total. How much did Bobby collect? *
Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

$432 dollars

Step-by-step explanation:

Elina [12.6K]3 years ago
3 0

Answer:

432 in total.

Step-by-step explanation:

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Factorize using identities (i) 1-64x³+48x²-12x
enot [183]

Answer:

(1 - 4x)³

Step-by-step explanation:

The first 2 terms are a difference of cubes and factor in general as

a³ - b³ = (a - b)(a² + ab + b²), thus

1 - 64x³

= 1³ - (4x)³

= (1 - 4x)(1 + 4x + 16x²)

Thus

1 - 64x³ + 48x² - 12x ← factor out 12x from each of the 2 terms

= (1 - 4x)(1 + 4x + 16x²) + 12x(4x - 1) ← factor out - 1 from (4x - 1)

= (1 - 4x)(1 + 4x + 16x²) - 12x(1 - 4x) ← factor out (1 - 4x) from the terms

= (1 - 4x)(1 + 4x + 16x² - 12x)

= (1 - 4x)(1 - 8x + 16x²) ← perfect square

= (1 - 4x)(1 - 4x)²

= (1 - 4x)³  ← in factored form

6 0
3 years ago
Good night everyone : )
valkas [14]

Answer:

Good night sagey!!!! sleep well

4 0
2 years ago
Please can someone help me out​
lara31 [8.8K]

Answer:

380.1

Step-by-step explanation:

Area = 22/7 × 11 × 11 =380.3

8 0
3 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
X+56<533. What is the solution of the inequality?
swat32
X<477


hope this helps<3
7 0
3 years ago
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