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AysviL [449]
3 years ago
11

So the question on the pic

Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

Explanation + answers

Because there are lengths going from 0 to 1, the lines must mean either decimals or fractions (we'll use fractions for this.)

1. There are twelve lines from 0 and 1, which we can use as the denominator for our fraction. This means the length of each line is 1/12.

2. In order to find where K's point is at, we simply need to count until we get to it. After counting, I see that K is on point 8/12, which we can simplify to get a smaller number. If we simplify once, we get 4/6, which we can again simplify to get 2/3. This gives us the answer K is on point 8/12 or 2/3.

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astra-53 [7]
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3 years ago
the roof at the tennis stadium opens 421 inches in 50 seconds how many inches does the roof open per secound
Basile [38]

Answer:

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Step-by-step explanation:

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Consider a circle whose size can vary. Let r represent the radius of the circle (in cm) and let C represent the circumference of
Firdavs [7]

Answer:

g (15) represents the radius (in cm) of a circle whose circumference is 15 cm

if g (a) = 15, then a represents the circumference (in cm) of a circle whose radius is 15cm

Step-by-step explanation:

In a circle the following relationship can be posed:

C = 2 \pi r

Let g be a function that determines the radius of the circle from the value of its circumference, so, you have:

g (C) =\frac{C}{2\pi}

Thus, g (15) represents the radius (in cm) of a circle whose circumference is 15 cm. You have to g (15) =\frac{15}{2\pi}.

On the other hand, if g (a) = 15, then a represents the circumference (in cm) of a circle whose radius is 15cm. You have to a=2 \pi(15) = 30 \pi

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3 years ago
Find the value of cos C rounded to the nearest hundredth, if necessary
Sindrei [870]

\bold{\frac{5}{13} or 0.38}

Answer:

Solution given:

here

by using Pythagoras law

hypotenuse =

\displaystyle\sqrt{adjacent ²+opposite ²}\\=\sqrt{15²+36²}=39

Cos C=\frac{adjacent} {hypotenuse}=\frac{15}{39}=\frac{5}{13} or{0.38}

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V= 1/3 pi r^2h
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