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AysviL [449]
3 years ago
11

So the question on the pic

Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

Explanation + answers

Because there are lengths going from 0 to 1, the lines must mean either decimals or fractions (we'll use fractions for this.)

1. There are twelve lines from 0 and 1, which we can use as the denominator for our fraction. This means the length of each line is 1/12.

2. In order to find where K's point is at, we simply need to count until we get to it. After counting, I see that K is on point 8/12, which we can simplify to get a smaller number. If we simplify once, we get 4/6, which we can again simplify to get 2/3. This gives us the answer K is on point 8/12 or 2/3.

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Simplify (Remember to simplify means to write an equivalent expression that uses each variable on')
DaniilM [7]

Answer:

A) x^{3} y^{4}

B) -\frac{5x^{2} }{y}

C) 9m^{4}n^{4}

D)\frac{1}{x^{3} }

Step-by-step explanation:

Hope this helps.

6 0
2 years ago
If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?
Ludmilka [50]

Answer:

Step-by-step explanation:

y = k*x                    This is the formula for a direct variation.

  • y = 20
  • x = 4                        Substitute these values into the direct variation

20 = 4 * k                        Divide by 4

20/4 = 4k/4

k = 5

Answer: the constant of variation is 5

7 0
2 years ago
An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away
daser333 [38]

The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0
3 years ago
Read 2 more answers
Modeling Exponential Growth and Decay In Exercises 119 and 120, Find the exponential function
Lubov Fominskaja [6]

Answer:

There is no exponential function passing through (1,1) and (5,5).

Step-by-step explanation:

We have the following exponential function

y = Ce^{kt}

The function passes through these two points:

(1,1): This means that when t = 1, y = 1

(5,5): This means that when t = 5, y = 5.

So

(1,1)

y = Ce^{kt}

Ce^{k} = 1

e^{k} = \frac{1}{C}

(5,5)

y = Ce^{kt}

5Ce^{k} = 1

Ce^{k} = \frac{1}{5}

From above, we have that:

e^{k} = \frac{1}{C}

C\frac{1}{C} = \frac{1}{5}

1 = \frac{1}{5}

1 cannot be equal to 1/5, so this is wrong.

This means that there is no exponential function passing through (1,1) and (5,5).

5 0
3 years ago
Keiko, Chang, and Abdul sent a total of 109 text messages over their cell phones during the weekend. Keiko sent 7 fewer messages
lbvjy [14]

9514 1404 393

Answer:

  • Keiko: 17
  • Chang: 24
  • Abdul: 68

Step-by-step explanation:

Let c represent the number of messages sent by Chang. Then Keiko sent (c-7) messages, and Abdul sent 4(c-7) messages. The total number sent was ...

  c + (c -7) +4(c -7) = 109

  6c -35 = 109 . . . . . . . . . . simplify

  6c = 144 . . . . . . . . . . . add 35

  c = 24 . . . . . . . . . . . divide by 6

  c-7 = 17

  4(c-7) = 68

Keiko sent 17, Chang sent 24, and Abdul sent 68 text messages.

5 0
3 years ago
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