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Alex73 [517]
2 years ago
5

The population of Kalona is currently 15,400 people. If the population decreases at an average rate of 325 people per year, how

many years it will take for the population to fall to 775 people?
Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0
We can use the equation 15,400 - 325x = 775. This is because the current population is 15,400, and 325 people leave yearly. X represents the amount of years, and we need to solve x to figure out how many years for the population to fall to 775.

We need to isolate x. We can do that by subtracting 15,400 from both sides. This gives us -325x = -14,625. Next, we need to divide both sides by -325. This gives us x = 45.

We can plug 45 into x to check our answer. 15,400 - 325(45) = 775. 15,400 - 14,625 = 775.

It will take 45 years for the population to fall to 775 people.
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I need help on this one thanks!!
mart [117]

Answer:

CU = 12

Step-by-step explanation:

Clearly from the diagram of the triangle we can say that,

AD, BE and CF are the medians of the triangle ABC , since they are bisecting the sides of the triangle equally.

Also , U is the intersection point of the these mediands of the triangle whic is known as centroid of the triangle.

Now, from the property of the centroid , centroid divides the median in the ratio of 2 :1 from the point C .

Thus CU will be \frac{2}{3} times of CF (median) .

Given is Cf equals 18 ,

Thus , CU = \frac{2}{3}×18 = 12.

So, CU equals 12 .

8 0
3 years ago
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alexandr1967 [171]

Answer:

The answer is -2

Step-by-step explanation:

you subtract common numbers, so:

5s - 3s = 2s

Then,

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You would then get

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5 0
4 years ago
A given line has the equation 2x+12y=-1.
PolarNik [594]
<span>2x+12y=-1
</span>y = -1x/6 -1/12

Perpendicular lines<span> are </span>lines<span> that cross one another at a 90° angle. They have slopes that are opposite reciprocals of one another. Therefore, the slope of the perpendicular line in this problem is the opposite reciprocal of -1/6 which is 6. The equation would be 

</span><span>y=(6)x+9</span>
4 0
3 years ago
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Is the expression 5(3m+2p)-4m equivalent to the expression 13p+11m-3p?<br>Explain your answer.
Damm [24]
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5 0
3 years ago
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Multiply
Dmitriy789 [7]

Answer:

The product of given two fractions is

\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Step-by-step explanation:

Given expression is  

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}

To find the product of two given fractions as below :

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{20x(x+2)}{5x(x-1)(x+3)}

=\frac{20x^2+40x}{(5x^2-5x)(x+3)} (multiply each term in the factor to each term in the another factor )

=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}  ( adding the like terms )

=\frac{20x^2+40x}{5x^3+10x^2-15x}

=\frac{5x(4x+8)}{5x(x^2+2x-3)}

=\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Therefore the product of given two fractions is \frac{4(x+2)}{(x-1)(x+3)}

6 0
3 years ago
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