All categories

3 years ago

-4/5=2b

Mathematics

2 answers:

Oliga [24]3 years ago

7 0

Answer:

Step-by-step explanation:

-4/5=2b

------------

-4/10 =b

rusak2 [61]3 years ago

5 0

B = -2/5

Divide each side by 2. 2b divided by 2 is equal to b and -4/5 divided by 2 is equal to-2/5

You might be interested in

Solve the system of linear equations below.

Mrac [35]

Answer:

I am not sure which one it is due to what you put in. I think it would be A.

x = 0

y = 2/3

Step-by-step explanation:

Step: Solve x + 6y= 4 for x:

x + 6y + −6y = 4 + −6y

x= −6y + 4

Step: Substitute −6y + 4 for x in 2x + 3y = 2:

2x + 3y = 2

2 (−6y + 4) + 3y = 2

−9y + 8 = 2

−9y + 8 + −8 = 2 + −8

−9y = −6

-9y/-9 = -6/-9

y = 2/3

Step: Substitute 2/3 for y in x = −6y + 4:

x = −6y + 4

x = -6 (2/3) + 4

x = 0

Sorry if it is long and confusing. But I hope this helps!

3 0

3 years ago

Name two obtuse angles

Katena32 [7]

Answer:

more than 90° or less than 180°

7 0

3 years ago

Find the missing side length CAN SOMEONE PLEASE HELP ME? PLEASEEEEE!!!

Ganezh [65]

Answer:

13.31803792

Step-by-step explanation:

Law of Cosines

a= 8

b= 18

c= ?

$c^2=a^2b^2-2ab*cos(c)$

$c^2=8^2-18^2-2*8*18*cos(43)$

c = 64 + 324 - 2 * 8 * 18 * cos(43)

cos(43) = 0.7313537016

Order of Operations

64 + 324 - 2 * 8 * 18 * 0.7313537016 = 177.3701339

Square Root the answer

$\sqrt{177.3701339}$ = 13.31803792

4 0

3 years ago

Read 2 more answers

What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0

3 years ago

What multiplied by itself 3 times gives you -216 please answer asap!!!

earnstyle [38]

6x6x6=216
Six multiply six equal 36 and multiply it again by six it will be 216

3 0

3 years ago