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Damm [24]
3 years ago
8

Convert this rational number

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

0.25

Step-by-step explanation:

1 divided by 4 = 0.25

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Reflect the point (a) in the x-axis and (b) in the y-axis <br>(4,5)<br>and <br>(1 1/2, -1/4)
gulaghasi [49]

(4,5)

a) -4,5

b) 4,-5

(11/2 , -1/4)

a)-11/2,-1/4

b)11/2,1/4

6 0
2 years ago
PLZ HELLP ASAP !!!!!!!!!!!!!!!
vovangra [49]

Answer:

Where is the question?

Step-by-step explanation:

4 0
2 years ago
Find the error and explain why its wrong
UNO [17]

Answer:

The last part.

Step-by-step explanation:

The error is only at the last part. Basically the answer part.

The answer should be —

13 \sqrt{5}

We don't multiply the square roots when adding or subtracting. That'd contradict the rules.

Here, we let the square root of five as x-term.

\sqrt{5}  = x

4 \sqrt{5}  + 9 \sqrt{5}  = 4x + 9x

As we add up, we would get 13x. Thrn we convert x-term back to square root of five.

The answer would be —

13x \\ x =  \sqrt{5}  \\ 13 \sqrt{5}

Remember that we don't multiply the square roots when adding or subtracting.

5 0
3 years ago
Suppose there's 0.01895 ml of propellant in one milliliter of spray paint. What's the amount of propellant rounded to the neares
ololo11 [35]

Answer:

The amount of propellant  is 52.770 ml of spray paint

Step-by-step explanation:

We are given

0.01895 ml of propellant in one milliliter of spray paint

so,

0.01895 ml of propellant = 1 milliliter of spray paint

We can divide both sides by 0.01895

\frac{0.01895}{0.01895} ml of propellant = \frac{1}{0.01895} ml of spray paint

1 ml of propellant = \frac{1}{0.01895} ml of spray paint

now, we can divide right side

and we get

1 ml of propellant = 52.770 ml of spray paint

The amount of propellant  is 52.770 ml of spray paint

5 0
3 years ago
Read 2 more answers
Thanks for the help!
Margarita [4]

The value of the quadratic equation evaluated at 0 is equal to 1.

<h3>How to evaluate a quadratic equation at a given x-value</h3>

In this question we have a quadratic equation and we need to evaluate the function at x = 0 and find the result by algebraic procedures. Now we proceed to evaluate the function:

g(x) = - 2 · x² + 1, x = 0                       Given

g(0) = - 2 · 0² + 1                                Previous step

g(0) = - 2 · 0 + 1                                  Cancellative theorem

g(0) = 0 + 1                                         Cancellative theorem

g(0) = 1 + 0                                         Commutative property

g(0) = 1                                               Modulative property / Result

The value of the quadratic equation evaluated at 0 is equal to 1.            

   

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

8 0
1 year ago
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