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kupik [55]
3 years ago
7

What is the perimeter of a rectangle with vertices located at (-3,-1). (5.-1). (5,9), and

Mathematics
2 answers:
bogdanovich [222]3 years ago
8 0

Answer:

116

Step-by-step explanation:

Find distance between (-3, -1) and (5, -1) --> 8

Find distance between (5, 9) and (5, -1) --> 10

Perimeter: 8 + 8 + 10 + 10 = 116

You can also literally just count the length of each side since it's on a graph

dezoksy [38]3 years ago
7 0

Answer:

36 units

Step-by-step explanation:

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What is the missing reason in the proof?
Tresset [83]
A. segment addition
3 0
2 years ago
What is 5 multiplied by 2
koban [17]

Answer:

10

Step-by-step explanation:

5x2 to me is basically adding 5 twice.

5+5=10

5x2=10

4 0
3 years ago
Read 2 more answers
A car moves at a constant speed of 90km/h from a starting point. Another car moves at 70km/h after 2hours from the same starting
patriot [66]

Step-by-step explanation:

are you sure you wrote the problem here correctly ?

because the distance will be 40km after less than half an hour just by the first car driving. way before the second car even starts.

to be precise, it would be after 60 minutes × 40 / 90

(= how many minutes of an hour are needed to reach 40km while going 90km/h) :

60 × 40 / 90 = 60 × 4 / 9 = 20 × 4 / 3 = 80/3 = 26.67 minutes.

but maybe the question was about 400km distance between the two cars.

so, the first car goes 90km/h for 2 hours.

at that moment it will be 2×90=180km ahead.

that would mean that 220km are still missing for the 400km assumption.

with each hour driving the first car makes 20km more than the second car.

to build up 220km that way would require

220/20 = 11 hours.

plus the 2 original head start hours this would make 13 hours as overall answer.

7 0
3 years ago
A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy
aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) \bar{B} y P(\bar{B})=0.5 (c) \bar{A}∪\bar{B} y P(\bar{A}∪\bar{B}) = 0.9 (d) \bar{A}∩\bar{B} y P(\bar{A}∩\bar{B})=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P(A\cap \bar{B}) = 0.3, P(B\cap \bar{A}) = 0.4 and P(A\cap B) = 0.1

(a) P(A) = P(A\cap (B\cup\bar{B})) = P(A\cap B) + P(A\cap \bar{B}) = 0.1 + 0.3 = 0.4

(b)  P(B) = P(B\cap (A\cup\bar{A})) = P(B\cap A) + P(B\cap \bar{A}) = 0.1 + 0.4 = 0.5

P( \bar{B}) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e.,  \bar{A}, and the customer does not buy from outlet 2 is the complement of B, i.e.,  \bar{B}, so, the customer does not buy from outlet 1 or does not buy from outlet 2 is  \bar{A}∪ \bar{B} and P(\bar{A}∪ \bar{B}) = P((A\cap B)^{c}) by De Morgan's laws

P((A\cap B)^{c})  = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to \bar{A}∩\bar{B} and P( \bar{A}∩\bar{B}) = P((AUB)^{c}) by De Morgan's laws, and

P((AUB)^{c}) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0
3 years ago
Ten thousand more than 300,000+90,000+5,000+40 is
Fed [463]
Add them together then add 10,000
4 0
3 years ago
Read 2 more answers
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