Which are lines that will intersect? which are perpendicular lines? which are skew lines?

Mathematics

1 answer:

Anarel [89]1 year ago

6 0

By using the concept of line, coplanar, non parallel lines always intersect

Definition of perpendicular and skew lines has been given

What is a line?

A geometrical object which has only length but no breadth and height is called a line

The lines which are coplanar and are not parallel will intersect at some point

Two lines are said to be perpendicular to each other if the angle between them is 90°

The lines which are not parallel, non coplanar at do not intersect are called skew lines.

To learn more about lines, refer to the link-

brainly.com/question/28045419

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The Midpoint of GH is M(4,-3). One endpoint is G(-2,2). Find the coordinates of endpoint H.

77julia77 [94]

Answer:

Step-by-step explanation:

(x - 2)/2 = 4

x - 2 = 8

x = 10

(y + 2)/2 = -3

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3 years ago

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uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

$(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20} \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}$

Q2)

Apply phythogoras theorem:

$CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4$

Q3)

Apply phythogoras theorem again:

$BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218} \\\\BC=\sqrt{218} \\\\BC=14.76$