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nadya68 [22]
2 years ago
8

Zac leaves for the airport at 6:52:10 am he drives for 1:15:47 at what time does zac Arrive the airport

Mathematics
1 answer:
otez555 [7]2 years ago
3 0

Answer:

8:07:57

Step-by-step explanation:

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12x +7 < −11 OR 5x −8 > 40
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For this case we must resolve each of the inequalities and find the solution set.

Inequality 1:

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We subtract 7 from both sides of the inequality:

12x

We divide between 12 on both sides of the inequality:

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Thus, the solution is given by all values of x less than- \frac {3} {2}.

Inequality 2:

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We add 8 to both sides of the inequality:

5x> 40 + 8\\5x> 48

We divide between 5 on both sides of the inequality:

x> \frac {48} {5}

Thus, the solution is given by all values of x greater than\frac {48} {5}.

The solution set is given by:

(-∞, - \frac {3} {2}) U (\frac {48} {5},∞)

Answer:

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Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)
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Rewrite g(x) as    x-1

                           ------

                              4

and then substitute this result for x in f(x) = x^2 - 3x + 3:

f(g(x)) = (x-1)^2 / 4^2 - 3(x-1)/4 + 3.

At this point we can substitute the value 5 for x:

f(g(5)) = (5-1)^2 / 4^2 - 3(5-1)/4 + 3

          = 16/16 - 3(4/4) + 3 = 1 - 3 + 3 = 1

Therefore, f(g(5)) = 1.

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