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romanna [79]
3 years ago
12

Answer...............

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

the dif is i would take the plus 9.5% each time cause you could always do over and get you salary even greater and it's better getting a plus then just the 450 every time

Step-by-step explanation:

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Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
How many times does 6 go into 22
sergeinik [125]
Hey!

We can use long division to solve this,
Let's write it.
6\overline{|\smallspace22}\space\space\space\space
Then, divide 22 by 6 to get 3.
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
Multiply the quotient by the divisor...
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
Subtract 18 from 22.
\begin{matrix}\space\space\space\space\space\space\emptyspace3\space\space\space\space\space\space\space\space\space\space\space\space\\ 6\overline{|\smallspace22}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\space\space\emptyspace4\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}
As you can see, our answer using long division would be 3 with a remainder of 4. 

Thanks!
-TetraFish
6 0
4 years ago
Read 2 more answers
What is the remainder when x2−4x+2 is divided by x+3?
Airida [17]
2x_45 I’m trying to figure it out but if I can get my text from work then I can go back to my dads house tonight and then I get off
5 0
2 years ago
Read 2 more answers
Product of (x+y)(2x+4y)
Oksanka [162]
When you multiply the equation out and you simplify like terms you get.


2x^2 + 6xy + 4y^2
3 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
a_sh-v [17]
For AC:
 AC= root((a-0)^2 + (b-0)^2)
 AC= root((a)^2 + (b)^2)
 For BD:
 AC= root((a-0)^2 + (0-b)^2)
 AC= root((a)^2 + (-b)^2)
 AC= root((a)^2 + (b)^2)

 Therefore,
 AC=BD
8 0
3 years ago
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