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3 years ago

Write an equation to match each graph:please help me?

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

Answer:

(1,5),(3,15),(5,25),(7,35)

Oksi-84 [34.3K]3 years ago

6 0

Y = 5x
Y is vertical axis, x is horizontal. Whatever the value of x is, y is 5 times that number

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A company sells tents in two styles, shown below. The sides and floor of each tent are made of nylon. Which tent requires less n

BartSMP [9]

Answer: Tunnel tent.

Step-by-step explanation:

The tent which has the minimum area requires less nylon to manufacture,

Since, the area of Pup tent = Area of 3 square each having side 8 ft + Area of 2 equilateral triangle having side 8 ft

= $3 \times ( 8^2 ) + 2\times \frac{64\sqrt{ 3} }{4}$

= $192+ 2\times \frac{64\sqrt{ 3} }{4}$

= $192+ 32\sqrt{ 3}$

= $247.425625842\approx 247.43\text { square ft}$

Now, the area of tunnel tent = Area of square having side 8 ft + total Area of half cylinder having radius 4 ft and height 8 ft

= $8^2 + \frac{1}{2} [ 2\pi\times 4(4+8)]$

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4 0

4 years ago

What is the value of x? -2/7x+6+1/7x=18 x=

Alenkinab [10]

$- \frac{2}{7} x$ + 6 + $\frac{1}{7} x$ = 18

First, simplify $\frac{2}{7} x$ to $\frac{2x}{7}$ / Your problem should look like: $-\frac{2x}{7}$ + 6 + $\frac{1}{7} x$ = 18
Second, simplify $\frac{1}{7} x$ to $\frac{x}{7}$ / Your problem should look like: $- \frac{2x}{7}$ + 6 + $\frac{x}{7}$ = 18
Third, simplify $- \frac{2x}{7}$ + 6 + $\frac{x}{7}$ to $- \frac{x}{7}$ + 6 / Your problem should look like: $-\frac{x}{7}$ + 6 = 18
Fourth, regroup terms. / Your problem should look like: 6 - $\frac{x}{7}$ = 18
Fifth, multiply both sides by 7. / Your problem should look like: 42 - x = 126
Sixth, subtract 42 from both sides. / Your problem should look like: -x = 126 - 42
Seventh, simplify 126 - 42 to 84. / Your problem should look like: -x = 84
Eighth, multiply both sides by -1. / Your problem should look like: x = -84

Answer: x = -84

4 0

3 years ago

Write an equation to match each graph:please help me?​

Write an equation to match each graph:please help me?