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3 years ago

SOMEONE PLS TELL ME IF IM RIGHT ILL MARK BRAINLIEST

Mathematics

2 answers:

Vlad1618 [11]3 years ago

5 0

Answer:

u r correct

look at the picture I sent

Oduvanchick [21]3 years ago

3 0

Answer:

Its actually 5 you were about 4 away

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In a bank of 320 staffs, 120 speak French, 140 speak English, 170 speak Arabic, 50 speak both French and English, 35 speak both

VMariaS [17]

I have no idea what the answer is

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3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

2 years ago

NEED HELP ASAP!!!!!!!

Elan Coil [88]

I think the answer is C

3 0

3 years ago

Which expression will help find the volume of the figure?

Alex Ar [27]

Answer:

9*4*1*2

Step-by-step explanation:

9×4×1×2

Its because you need all the values to find the volume

7 0

3 years ago

A bag contains counters that are red, black , or green . 1/3 of the counters are red 1/6 of the counters are black There are 15

Nadya [2.5K]

Answer:

There are 5 black counters in the bag.

Step-by-step explanation:

15 green counters in the bag

The proportion of green counters is given by:

$p = 1 - (\frac{1}{3} + \frac{1}{6}) = 1 - (\frac{2}{6}+\frac{1}{6}) = 1 - \frac{3}{6} = 1 - \frac{1}{2} = \frac{2}{2} - \frac{1}{2} = \frac{1}{2}$

So, we have that, the total is x. So

$\frac{x}{2} = 15$

$x = 30$

There are 30 total counters.

How many black counters are in the bag ?

A sixth of the counters are black. So

$\frac{1}{6} \times 30 = \frac{30}{6} = 5$

There are 5 black counters in the bag.

8 0

2 years ago