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MissTica
3 years ago
13

I NEED HELP ON BOTH OF THEM.

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0

Answer:

Q 1 is option B and q 2 is option D

Step-by-step explanation:

hichkok12 [17]3 years ago
4 0
B&D are the right answers
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<img src="https://tex.z-dn.net/?f=5%5E%7B-3%7D" id="TexFormula1" title="5^{-3}" alt="5^{-3}" align="absmiddle" class="latex-form
AveGali [126]

Answer:

the equivalent equation of

5^{-3}=\frac{1}{5^{3}}=\frac{1}{125}

5 0
2 years ago
HELPP!!! WILL GIVE BRAINLIEST AND 5 STARS!!!
seraphim [82]

Answer:

F=73.74 degrees

Step-by-step explanation:

sin=opposite/hypotenuse

opp=24 hyp=25

sin(F)=24/25 (to find angle have to use inverse sin)

sin-1(24/25)=73.74

6 0
3 years ago
Someone help me please !!!
KIM [24]

Answer:

1. 10

2. 12

3. Sqrt 130

4. Sqrt 45

Step-by-step explanation:

To find the missing side of a right triangle, use the Pythagorean Theorem. The Pythagorean Theorem is a^2+b^2=c^2 where a and b are the legs with a being the smallest and c is the hypotenuse.

1. a=6, b=8, c=?

6^2+8^2=c^2\\36+64=c^2\\100=c^2\\10=c

2. a=5, b=?, c=13

5^2+b^2=13^2\\25+b^2=169\\169-25=b^2\\144=b^2\\12=b

3. a=7, b=9, c=?

7^2+9^2=c^2\\49+81=c^2\\130=c^2\\\sqrt{130}=c

4. a=2, b=?, c=7

2^2+b^2=7^2\\4+b^2=49\\49-4=b^2\\45=b^2\\\sqrt{45}=b

5 0
3 years ago
Does this table represent a proportional relationship?<br><br> A) Yes<br> B) No
Nonamiya [84]

Answer:

a

Step-by-step explanation:

it is all doubles

7 0
3 years ago
Read 2 more answers
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
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