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andrezito [222]
3 years ago
5

Even the 2 figures are similar what scale factor can be used upon the missing length X.

Mathematics
1 answer:
Papessa [141]3 years ago
8 0
B) 1/2
It’s b if you do the work you will find that out
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Find m_ABD and mZCBD given m ABC = 77º. A (3x + 22) D 16 (5x - 17) B C mZ ABD |° and mZCBD​
Nostrana [21]

Answer:

∠ ABD = 49°, ∠ CBD = 28°

Step-by-step explanation:

∠ ABD + ∠ CBD = ∠ ABC , substitute values

3x + 22 + 5x - 17 = 77 , that is

8x + 5 = 77 ( subtract 5 from both sides )

8x = 72 ( divide both sides by 8 )

x = 9

Thus

∠ ABD = 3x + 22 = 3(9) + 22 = 27 + 22 = 49°

∠ CBD = 5x - 17 = 5(9) - 17 = 45 - 17 = 28°

4 0
3 years ago
Ms. Green tells you that a right triangle has a hypotenuse of 12 and a leg of 5. She asks you to find the other leg of the trian
Anit [1.1K]

let the other leg be x cm.

(5)^2+(x)^2=(12)

25+(x)^2=144

(x)^2=144-25

x=√119

x=10.9

5 0
3 years ago
Read 2 more answers
How many ounces of a ​17 % alcohol solution must be mixed with 4 ounces of a 20 ​% alcohol solution to make a 19 ​% alcohol​ sol
andre [41]

Answer:

  • 4 ounces

Step-by-step explanation:

Let the required amount is x.

<u>Alcohol content is same at the end:</u>

  • x*0.17 + 4*0.2 = (x + 4)*0.19
  • 0.17x + 0.8 = 0.19x + 0.72
  • 0.19x - 0.17x = 0.8 - 0.72
  • 0.02x = 0.08
  • x = 0.08/0.02
  • x = 4
5 0
3 years ago
Assume that abc = pqr. Which of the following congruence statements are correct? Check all that apply
allsm [11]

Answer:

A and E are correct congruence statements.

8 0
3 years ago
Use euler's theorem to find a number x between 0 and 28 with x85 congruent to 6 modulo 35.
Elan Coil [88]
Problem: find 0 &le; x &le; 28 such that x^85 ≡ 6 modulo 35.

By Fermat-Euler theorem:
If a and n are coprime, i.e. (a,n)=1, then
a^phi(n) ≡ 1 mod n  
where phi(n)=totient function, the number of positive integers less than n that is coprime with n.

for n=35, phi(35)=24 calculated as follows:
There are 10 positive integers from 1 to 34 which are NOT coprime with 35, namely {5,7,10,14,15,20,21,25,28,30}.Therefore phi(35)=34-10=24

From Fermat-Euler theorem, 
x^(phi(35) = x^24 ≡ 1 modulo 35  since (24,35)=1, i.e. 24 and 35 are coprime.
=>
x^12 ≡ &pm; 1 modulo 35. ...........(1)

and 

x^85 ≡ x^(85-3*24) ≡ x^(85-72) ≡ x^(13) ≡ 6 mod 35 ............(2)

Substituting (1) in (2)
x^(12)*x ≡ 6 mod 35
=>
(+1)*x = 6 mod 35   or  (-1)*x ≡ 6 mod 35
x ≡ 6 mod 35           x ≡ -6 mod 35   (rejected)

=>  x=6 

So

6^85 ≡ 6 mod 35


If any clarifications are needed or if you find any errors, please post.
5 0
3 years ago
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