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Bond [772]
3 years ago
10

(1 po

Mathematics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

The measure of ∠JHG is 70 degrees

Step-by-step explanation:

If you have one of angle's sides by 0° at protractor then the other side crosses the measure of angle.

Hope this helps

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Steve and Marcia bought soda, chips, and gum. • They bought twice as many chips as pieces of gum. • They bought 3 fewer sodas th
serg [7]

Answer:

ok so S=soda C=chips and G=gum

Step-by-step explanation:

From the information,

s+3=c

(1/2)c=g

from this P=s+c+g

P=s+(s+3)+((s+3)/2)

P=5/2s+9/2

7 0
3 years ago
Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th
Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0

5 0
3 years ago
Read 2 more answers
Please help quickly !
bixtya [17]

Answer:

A

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Someone please help ?????
Amiraneli [1.4K]
U=40
I think am sure
8 0
3 years ago
The box plots below show the distribution of salaries, in thousands, among employees of two small companies.
Shtirlitz [24]

Answer:

Mean and IQR

Step-by-step explanation:

The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.

For company A:

Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.

Hence, the mean will be the best measure of centre rather Than the median in this case.

For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.

7 0
3 years ago
Read 2 more answers
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