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satela [25.4K]
3 years ago
7

Cendrick D'Amitrano works Friday and Saturday delivering pizza. He delivers 8 pizzas on Friday. How many pizzas must he deliver

on Saturday to average (mean) 11 pizzas per day?
Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

14

Step-by-step explanation:

there are two days whose mean is 11.for you to get the mean of 11 you had divided by 2

multiply 11 by 2 which is 22

then minus fridays which is 8

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Which number is composed of exactly 8
Keith_Richards [23]

Answer:

B is the answer

Step-by-step explanation:

because it said 8 thousands so you know its not D and it says 7 tens so you know its not C and for 9 sense the hundredths has (ths) you know it's not A so the answer is B.

6 0
2 years ago
Read 2 more answers
Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro
tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation  

n=2700 represent the random sample taken    

X represent the people in England who are deficient in Vitamin D

\hat p=0.2 estimated proportion of England people who are deficient in Vitamin D

\alpha=0.02 represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)    

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

And replacing into the confidence interval formula we got:

0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182

0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0
3 years ago
The product of x and y is less than or equal to 4.
timama [110]

Answer:

xy (less than or equal to sign) 4

5 0
4 years ago
A hand consists of 1 card drawn from a standard 52-card deck with flowers on the back and 1 card drawn from a standard 52-card d
miskamm [114]

Answer:

A)   2704 hands

B)   16 hands

C)   144 hands

D)   384 hands

E)   208 hands

F)   400 hands

Step-by-step explanation:

See the attached file for explanation

8 0
3 years ago
Estimate : 1) 48% of 8 2) 3% of 119 3) 26% of 32 4) 76% of 280
zaharov [31]
1) 48% of 8=3.84 
2) 3% of 119=3.57
3) 26% of 32=8.32
4) <span>76% of 280=212.8

Hope this helps ya!</span>
7 0
3 years ago
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